H(t)=t^2+2t+3

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Solution for H(t)=t^2+2t+3 equation: 



(H)=H^2+2H+3

We move all terms to the left:

(H)-(H^2+2H+3)=0

We get rid of parentheses

-H^2+H-2H-3=0

We add all the numbers together, and all the variables

-1H^2-1H-3=0

a = -1; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·(-1)·(-3)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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